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5x^2-17.5x-10=0
a = 5; b = -17.5; c = -10;
Δ = b2-4ac
Δ = -17.52-4·5·(-10)
Δ = 506.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17.5)-\sqrt{506.25}}{2*5}=\frac{17.5-\sqrt{506.25}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17.5)+\sqrt{506.25}}{2*5}=\frac{17.5+\sqrt{506.25}}{10} $
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